Suppose we are trying to prove that
\(a\) is the least upper bound of a set
\(S\text{.}\) Then we need prove that the two defining properties of the supremum hold for
\(a\text{.}\) In order to prove the statement “if
\(b\) is an upper bound for
\(S\text{,}\) then
\(a\leq b\text{,}\)” it may be easier to show the contrapositive, “if
\(b \lt a\text{,}\) then
\(b\) is not an upper bound for
\(S\text{.}\)” In order to prove that contrapositive, we need to show that for any
\(b \lt a\text{,}\) there is some
\(s\in S\) so that
\(s \gt b\text{.}\) Then
\(b\) will not be an upper bound for
\(S\text{,}\) by definition.