Let \(f :\mathbb R\rightarrow \mathbb R\) be a function which is defined by \(f(x)=\dfrac{2x}{1+x^2}\text{.}\) Show that \(f(\mathbb R)=[-1,1]\text{.}\)
Find: \(f\big(\{1,2,3\}\big)\text{,}\)\(f\big(\{4,5,6,7\}\big)\text{,}\)\(f(\emptyset)\text{,}\)\(f^{-1}\big(\{0,5,9\}\big)\) and \(f^{-1}\big(\{0,3,5,9\}\big)\text{.}\)
Let \(f:\mathbb R\to\mathbb R\) be the function defined by \(f(x) = x^2+ax+b\text{,}\) where \(a,b\in\mathbb R\text{.}\) Determine whether \(f\) is injective and/or surjective.
Determine all functions \(f:\mathbb N \rightarrow \mathbb N\) that are injective and such that for all \(n\in \mathbb N\) we have \(f(n)\leq n\text{.}\)
For \(n\in\mathbb{N}\text{,}\) let \(A=\{ a_1, a_2, a_3,\cdots, a_n \}\) be a fixed set where \(a_j\neq a_i\) for any \(i\neq j\text{,}\) and let \(F\) be the set of all functions \(f: A\rightarrow \{ 0,1 \}\text{.}\)
Let \(f : \mathbb{Z} \rightarrow \mathbb{Z}\times\mathbb{Z}\) be defined by \(f(n) = (2n+1, n + 2)\text{.}\) Check whether this function is injective and whether it is surjective. Prove your answer.
Let \(f:E\rightarrow F\) be a function. We recall that for any \(A\subseteq E\) the image of \(A\) by \(f\text{,}\) namely \(f(A)\text{,}\) is defined as
Let \(A, B\) be nonempty sets. Prove that if there is a bijection \(f:A\rightarrow B\text{,}\) then there is a bijection from \(\mathcal{P}(A)\text{,}\) the power set of \(A\text{,}\) to \(\mathcal{P}(B)\text{,}\) the power set of \(B\text{.}\)
Let \(n\in\mathbb{N}\) with \(n\gt 1\) and let \(\mathbb{Z}_n\) be the set of equivalence classes modulo \(n\text{.}\) For any \(x\in\mathbb{Z}\text{,}\) let \([x]_n \in \mathbb{Z}_n\) denote its equivalence class modulo \(n\text{.}\)
Define the function \(f:\mathbb{Z}_n\to \set{0,1,\dots,n-1}\) by \(f([x]_n)=r\text{,}\) where \(r\) is the remainder of \(x\) upon division by \(n\text{.}\)
Show that \(f\) is well-defined, meaning that \(f\) is defined on its whole domain and that \(f\) does not depend on the choice of representative for each equivalence class; i.e. \([x]_n=[y]_n \implies f([x]_n)=f([y]_n)\text{.}\)
This question explains why when dealing with equivalence classes of integers modulo \(n\text{,}\) we often consider the set of representatives \(\set{0,1,\dots,n-1}\) instead.
We say that a function \(f:\mathbb{R}\to \mathbb{R}\) is strictly increasing if whenever \(x_1 \lt x_2\) we have \(f(x_1) \lt f(x_2)\text{.}\) Similarly, a function \(g: \mathbb{R}\to \mathbb{R}\) is strictly decreasing if whenever \(x_1 \lt x_2\) we have \(g(x_1) \gt g(x_2)\text{.}\)
Prove that the composition of two strictly increasing functions is strictly increasing.
Consider the following functions and their compositions.
Let \(f:\mathbb{R}\to \mathbb{R}\) be defined by \(f(x)=x+1\text{.}\) Does there exist a function \(g:\mathbb{R}\to \mathbb{R}\) such that \((f\circ g )(x) = (g\circ f)(x)\) for every \(x\in \mathbb{R}\text{?}\)
Let \(f:\mathbb{R}\to \mathbb{R}\) be defined by \(f(x)=c\) for some \(c\in \mathbb{R}\) (i.e. \(f\) is a constant function). Which functions \(g:\mathbb{R}\to \mathbb{R}\) have the property \((f\circ g) (x) = (g\circ f)(x)\) for every \(x\in \mathbb{R}\text{?}\)
Let \(f:\mathbb{R}\to \mathbb{R}\text{.}\) Suppose \((f\circ g)(x) = (g\circ f)(x)\) for every \(x\in \mathbb{R}\) and for every function \(g:\mathbb{R}\to \mathbb{R}\text{.}\) Show that \(f(x) = x\text{.}\)
Let \(f:\mathbb Z \rightarrow \mathbb Z\) defined so that \(f(n)=-n+3\) if \(n\) is even and \(f(n)=n+7\) if \(n\) is odd. Prove that \(f\) is bijective and find its inverse, \(f^{-1}\text{.}\)
The following question concerns the triple composition of a function.
Let \(A\) be a non-empty set and let \(g:A \to A\) be a function that satisfies \(g\circ g\circ g=i_A\text{,}\) where \(i_A\) is the identity function on the set \(A\text{.}\) Prove that \(g\) must be bijective.